1-3*sinx^2=cos(x)

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Solution for 1-3*sinx^2=cos(x) equation:


Simplifying
1 + -3sinx2 = cos(x)

Multiply cos * x
1 + -3insx2 = cosx

Solving
1 + -3insx2 = cosx

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -3insx2 = -1 + cosx

Combine like terms: 1 + -1 = 0
0 + -3insx2 = -1 + cosx
-3insx2 = -1 + cosx

Divide each side by '-3nsx2'.
i = 0.3333333333n-1s-1x-2 + -0.3333333333cn-1ox-1

Simplifying
i = 0.3333333333n-1s-1x-2 + -0.3333333333cn-1ox-1

Reorder the terms:
i = -0.3333333333cn-1ox-1 + 0.3333333333n-1s-1x-2

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